Programming, Data Structures And Algorithms Using Python - Week 4 Quiz | NPTEL | [Jan 2023]

Consider the following Python function.

def mystery(l):
if (l == []):
return(l)
else:
mid = len(l)//2
if (len(l)%2 == 0):
return l[mid-1:mid+1] + mystery(l[:mid-1]+l[mid+1:])
else:
return l[mid:mid+1] + mystery(l[:mid]+l[mid+1:])

What does mystery([22,14,19,65,82,55]) return?

[19, 65, 14, 82, 22, 55]

What is the value of triples after the following assignment? triples = [ (x,y,z) for x in range(1,4) for y in range(2,5) for z in range(5,8) if x+y > z ]

[(2, 4, 5), (3, 3, 5), (3, 4, 5), (3, 4, 6)]

Consider the following dictionary. marks = {"Quizzes":{"Mahesh":[3,5,7,8],"Suresh":[9,4,8,8],"Uma":[9,9,7,6]},"Exams":{"Mahesh":[37],"Uma":[36]}} Which of the following statements does not generate an error?

a. marks["Exams"]["Suresh"].extend([44])
b. marks["Exams"]["Suresh"] = [44]
c. marks["Exams"]["Suresh"].append(44)
d. marks["Exams"]["Suresh"][0:] = [44]

b. marks["Exams"]["Suresh"] = [44]

Option 1: Output KeyError: 'Suresh'

Option 2:Output {'Quizzes': {'Mahesh': [3, 5, 7, 8], 'Suresh': [9, 4, 8, 8], 'Uma': [9, 9, 7, 6]}, 'Exams': {'Mahesh': [37], 'Uma': [36], 'Suresh': [44]}}

Option 3: Output KeyError: 'Suresh'

Option 4: Output KeyError: 'Suresh'

Assume that actor has been initialized as an empty dictionary: actor = {} Which of the following generates an error?

a. actor["Star Wars"] = ["Rey","Ridley"]
b. actor["Star Wars, Rey"] = "Ridley"
c. actor[["Star Wars", "Rey"]] = "Ridley"
d. actor[("Star Wars", "Rey")] = "Ridley"

c. actor[["Star Wars", "Rey"]] = "Ridley"

Option 1: Output
{'Star Wars': ['Rey', 'Ridley']}

Option 2: Output
{'Star Wars, Rey': 'Ridley'}

Option 3: Output
TypeError: unhashable type: 'list'

Option 4: Output
{('Star Wars', 'Rey'): 'Ridley'}

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